5 Ounce Force Feet in Kilonewton Decimeters

How many Kilonewton Decimeters are in 5 Ounce Force Feet?

The answer is 5 Ounce Force Feet is equal to 0.004236931070468 Kilonewton Decimeters and that means we can also write it as 5 Ounce Force Feet = 0.004236931070468 Kilonewton Decimeters. Feel free to use our online unit conversion calculator to convert the unit from Ounce Force Foot to Kilonewton Decimeter. Just simply enter value 5 in Ounce Force Foot and see the result in Kilonewton Decimeter. You can also Convert 6 Ounce Force Feet to Kilonewton Decimeters

How to Convert 5 Ounce Force Feet to Kilonewton Decimeters (5 ozf·ft to kN·dm)

By using our Ounce Force Foot to Kilonewton Decimeter conversion tool, you know that one Ounce Force Foot is equivalent to 0.0008473862140936 Kilonewton Decimeter. Hence, to convert Ounce Force Foot to Kilonewton Decimeter, we just need to multiply the number by 0.0008473862140936. We are going to use very simple Ounce Force Foot to Kilonewton Decimeter conversion formula for that. Pleas see the calculation example given below.

What is Ounce Force Foot Unit of Measure?

Ounce Force Foot is a unit of measurement for torque. One ounce force foot is equal to the torque resulting from a force of one ounce force applied perpendicularly to the end of moment arm that has length of one foot.

What is the symbol of Ounce Force Foot?

The symbol of Ounce Force Foot is ozf·ft. This means you can also write one Ounce Force Foot as 1 ozf·ft.

What is Kilonewton Decimeter Unit of Measure?

Kilonewton Decimeter is a unit of measurement for torque. One kilonewton decimeter is equal to the torque resulting from a force of one kilonewton applied perpendicularly to the end of moment arm that has length of one decimeter.

What is the symbol of Kilonewton Decimeter?

The symbol of Kilonewton Decimeter is kN·dm. This means you can also write one Kilonewton Decimeter as 1 kN·dm.

Convert 5 Ounce Force Foot to Other Torque Units