7 Newton/Foot in Pound Force/Inch

How many Pound Force/Inch are in 7 Newton/Foot?

The answer is 7 Newton/Foot is equal to 0.1311385501415 Pound Force/Inch and that means we can also write it as 7 Newton/Foot = 0.1311385501415 Pound Force/Inch. Feel free to use our online unit conversion calculator to convert the unit from Newton/Foot to Pound Force/Inch. Just simply enter value 7 in Newton/Foot and see the result in Pound Force/Inch. You can also Convert 8 Newton/Foot to Pound Force/Inch

How to Convert 7 Newton/Foot to Pound Force/Inch (7 N/ft to lbf/in)

By using our Newton/Foot to Pound Force/Inch conversion tool, you know that one Newton/Foot is equivalent to 0.018734078591643 Pound Force/Inch. Hence, to convert Newton/Foot to Pound Force/Inch, we just need to multiply the number by 0.018734078591643. We are going to use very simple Newton/Foot to Pound Force/Inch conversion formula for that. Pleas see the calculation example given below.

What is Newton/Foot Unit of Measure?

Newton per foot is a unit of measurement for surface tension. Surface tension is considered to be equal to one newton per foot if the force along a line of one foot length, where the force is parallel to the surface but perpendicular to the line is equal to one newton.

What is the symbol of Newton/Foot?

The symbol of Newton/Foot is N/ft. This means you can also write one Newton/Foot as 1 N/ft.

What is Pound Force/Inch Unit of Measure?

Pound force per inch is a unit of measurement for surface tension. Surface tension is considered to be equal to one pound force per inch if the force along a line of one inch length, where the force is parallel to the surface but perpendicular to the line is equal to one pound force.

What is the symbol of Pound Force/Inch?

The symbol of Pound Force/Inch is lbf/in. This means you can also write one Pound Force/Inch as 1 lbf/in.

Convert 7 Newton/Foot to Other Surface Tension Units