9 Dyne/Inch in Pond/Foot

How many Pond/Foot are in 9 Dyne/Inch?

The answer is 9 Dyne/Inch is equal to 0.11012935100162 Pond/Foot and that means we can also write it as 9 Dyne/Inch = 0.11012935100162 Pond/Foot. Feel free to use our online unit conversion calculator to convert the unit from Dyne/Inch to Pond/Foot. Just simply enter value 9 in Dyne/Inch and see the result in Pond/Foot. You can also Convert 10 Dyne/Inch to Pond/Foot

How to Convert 9 Dyne/Inch to Pond/Foot (9 dyn/in to p/ft)

By using our Dyne/Inch to Pond/Foot conversion tool, you know that one Dyne/Inch is equivalent to 0.012236594555735 Pond/Foot. Hence, to convert Dyne/Inch to Pond/Foot, we just need to multiply the number by 0.012236594555735. We are going to use very simple Dyne/Inch to Pond/Foot conversion formula for that. Pleas see the calculation example given below.

What is Dyne/Inch Unit of Measure?

Dyne per inch is a unit of measurement for surface tension. Surface tension is considered to be equal to one dyne per inch if the force along a line of one inch length, where the force is parallel to the surface but perpendicular to the line is equal to one dyne.

What is the symbol of Dyne/Inch?

The symbol of Dyne/Inch is dyn/in. This means you can also write one Dyne/Inch as 1 dyn/in.

What is Pond/Foot Unit of Measure?

Pond per foot is a unit of measurement for surface tension. Surface tension is considered to be equal to one pond per foot if the force along a line of one foot length, where the force is parallel to the surface but perpendicular to the line is equal to one pond.

What is the symbol of Pond/Foot?

The symbol of Pond/Foot is p/ft. This means you can also write one Pond/Foot as 1 p/ft.

Convert 9 Dyne/Inch to Other Surface Tension Units