9 Ampere/Foot in Biot/Inch

How many Biot/Inch are in 9 Ampere/Foot?

The answer is 9 Ampere/Foot is equal to 0.075 Biot/Inch and that means we can also write it as 9 Ampere/Foot = 0.075 Biot/Inch. Feel free to use our online unit conversion calculator to convert the unit from Ampere/Foot to Biot/Inch. Just simply enter value 9 in Ampere/Foot and see the result in Biot/Inch. You can also Convert 10 Ampere/Foot to Biot/Inch

How to Convert 9 Ampere/Foot to Biot/Inch (9 A/ft to Bi/in)

By using our Ampere/Foot to Biot/Inch conversion tool, you know that one Ampere/Foot is equivalent to 0.0083333333333333 Biot/Inch. Hence, to convert Ampere/Foot to Biot/Inch, we just need to multiply the number by 0.0083333333333333. We are going to use very simple Ampere/Foot to Biot/Inch conversion formula for that. Pleas see the calculation example given below.

What is Ampere/Foot Unit of Measure?

Ampere per foot is a unit of measurement for linear current density. It is defined as flow of current in ampere through a conductor which is one foot wide.

What is the symbol of Ampere/Foot?

The symbol of Ampere/Foot is A/ft. This means you can also write one Ampere/Foot as 1 A/ft.

What is Biot/Inch Unit of Measure?

Biot per inch is a unit of measurement for linear current density. It is defined as flow of current in biot through a conductor which is one inch wide.

What is the symbol of Biot/Inch?

The symbol of Biot/Inch is Bi/in. This means you can also write one Biot/Inch as 1 Bi/in.

Convert 9 Ampere/Foot to Other Linear Current Density Units